随机温习...
(接前: 10 04 03) “执行定理” 的证明(d+). .
There is a prime divisor T on birational models of X such that a(T, X, B + sL) = eps'.
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18 19 24 25
28
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注: 这句话是由 (X, B+sL) eps'-lc 推出(按定义).
---- 18, 19, 24, 25: X, B, L, s. (已定义)
---- 28: T.
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Let x be the generic point of the centre of T on X.
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18 28
29
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注: 以 X 和 T 做为基础, 设置母点.
---- 29: x 为 T 的中心的母点.
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Assume x is not a closed point.
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18
30
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注: 假定 x 非闭.
---- 30: x 非闭.
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Then cutting by general elements of |A| and applying induction, there is a positive number v bounded from below away from zero such that (X, B + vL) is lc near x.
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0 i
31 32
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注: 第四段关键句.
---- 0: 归纳假设.
---- i: cutting by general elements of |A|.
(红色表示特定技术)
---- 31: v 有正下界.
---- 32: (X, B + vL) lc near x.
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Then (X, B + (1 - eps'/eps)vL) is eps'-lc near x, by Lemma 2.3, because B + (1 - eps'/eps)vL = eps'/eps B + (1 - eps'/eps) (B + vL).
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0 a 32
33
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注: 由 eps-lc 和 lc 造 eps'-lc.(令 = eps'/eps).
---- 33: (X, B + (1 - eps'/eps)vL) eps'-lc near x.
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In particular, s ≥ (1 - eps'/eps)v.
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25 33
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注: eps'-lc 状态, s 最大.
---- 34: s ≥(1 - eps'/eps)v.
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Thus we can assume x is a closed point.
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注: 此段的第二个结论.
---- 35: x 系 closed point.
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评论: 从上下文分析, 31,33 可能是35的逻辑前导.(?).
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小结: 这个第四段是重点.(closed point 概念待考)
符号大全、上下标.|| 常用:↑↓ π ΓΔΛΘΩμφΣ∈ ∉ ∪ ∩ ⊆ ⊇ ⊂ ⊃ ≤ ≥ ⌊ ⌋ ⌈ ⌉ ≠ ≡ ⁻⁰ ¹ ² ³ ᵈ ₀ ₁ ₂ ₃ ᵢ .